a) 44655
b) 44755
c) 44855
d) 44955
333 times 135 = 333 × 135 = 44955
2. What will come in place of the question mark in the following equation?
(49/10) + (3/11) + (7/15) = ?
a) 5 (213/330)
b) 5 (211/330)
c) 5 (215/330)
d) 5 (217/330)
(49/10) + (3/11) + (7/15) = ?
⇒ [(49 × 33) + (3 × 30) + (7 × 22)]/330
⇒ (1617 + 90 + 154)/330
⇒ 1861/330
⇒ 5 (211/330)
3. What should come in place of the question mark (?) in the following question?
1/4th of 1/2 of 3/4th of 52000 = ?
a) 4475
b) 4575
c) 4775
d) 4875
1/4th of 1/2 of 3/4th of 52000
⇒ (1/4) × (1/2) × (3/4) × 52000
⇒ (52000 × 3)/32
⇒ 1625 × 3
⇒ 4875
4. What will come in place of question mark in the following equation?
283 × 56 + 252 = 20 × ?
a) 905
b) 605
c) 805
d) 705
283 × 56 + 252 = 20 × x
⇒ 15848 + 252 = 20 × x
⇒ 16,100 = 20 × x
⇒ x = 805
5. What will come in place of question mark (?) in the following question?
(5863 - √2704) × 0.5 = ?
a) 2705.5
b) 2605.5
c) 2905.5
d) 2805.5
(5863 - √2704) × 0.5 = x
⇒ (5863 – 52) × 0.5 = x
⇒ x = 2905.5
6. What will come in place of question mark (?) in the following question?
76% of 1285 = 35% of 1256 + ?
a) 527
b) 537
c) 547
d) 557
76% of 1285 = 35% of 1256 +?
⇒ (76/100) × 1285 = (35/100) × 1256 +?
⇒ 97660/100 = 43960/100 +?
⇒ ? = (97660/100) – (43960/100)
⇒ ? = 53700/100 = 537
7. In the following question, two equations numbered I and II are given. You have to solve both the equations and give answer
I. √500 x + √402 = 0
II. √360 y + √200 = 0
a) x < y
b) x > y
c) x = y
d) none of the above
x = -√402/√500 = -√(402 × 18)/√(500 × 18) = -√7236/√9000
y = -√200/√360 = -√(200 × 25)/√(360 × 25) = -√5000/√9000
Now, as -√7236 < -√5000
Hence, x < y.
8. The sum of 15% of a positive number and 20% of the same number is 126.What is one-third of that number?
a) 100
b) 120
c) 140
d) 160
Let the number = x
According to the question
⇒ (15/100) × x + (20/100) × x = 126
⇒ (35/100) × x = 126
⇒ x = 12600/35 = 360
We want to find out x/3
∴ x/3 = 360/3 = 120
9. If 70% of a number is subtracted from itself it reduces to 81.what is two fifth of that no.?
a) 108
b) 118
c) 98
d) 128
Let the number be m.
Then m – 70 % of m = 81
⇒ m – 70/100 × m = 81
⇒ m – 0.7m = 81
⇒ 0.3m = 81
⇒ m = 81/0.3
⇒ m = 270
According to question:
Now, we need to find 2m/5
= 2 × 270 / 5
= 2 × 54
= 108
10. What will come in the place of the question mark '?' in the following question?
986 × 237 + 986 × 863 = ?
a) 1064600
b) 1074600
c) 1094600
d) 1084600
We are given 986 x 237 + 986 x 863
Hence taking 986 common
We have 986 × (237 + 863)
? = 986 × 1100
? = 1084600